AP EAMCET · Maths · Circle
If the lines and lie along diameters of a circle of area then the equation of the circle is
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(A)
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Given: the lines x+2y-5=0 and 2x-3y+4=0 lie along diameters of a circle of area 9π We have πr2=9π⇒r2=9 The intersection point of given lines will be center of the circle 2x+4y=10-(2x-3y=-4)7y=14⇒y=2, x=1 So the equation of circle is x-12+y-22=9…
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