AP EAMCET · PHYSICS · Mechanical Properties of Fluids
If two soap bubbles \(A\) and \(B\) of radii \(r_1\) and \(r_2\) respectively are kept in vaccum at constant temperature, then the ratio of masses of air inside the bubbles \(A\) and \(B\) is
- A \(r_2^2: r_1^2\)
- B \(\mathrm{r}_1^2: \mathrm{r}_2^2\)
- C \(r_1: r_2\)
- D \(r_2: r_1\)
Answer & Solution
Correct Answer
(B) \(\mathrm{r}_1^2: \mathrm{r}_2^2\)
Step-by-step Solution
Detailed explanation
\( P = \frac{4T}{r} \) \( m = \frac{PV M}{RT} \) \( \frac{m_A}{m_B} = \frac{P_A V_A}{P_B V_B} = \frac{(\frac{4T}{r_1}) (\frac{4}{3}\pi r_1^3)}{(\frac{4T}{r_2}) (\frac{4}{3}\pi r_2^3)} \) \( \frac{m_A}{m_B} = \frac{r_1^2}{r_2^2} \)
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