AP EAMCET · Chemistry · Coordination Compounds
The configurations of the complexes of manganese A, B respectively are \(t_{2 g}^3 e_g^1, t_{2 g}^4 e_g^0\). Then \(A, B\) are
- A \(\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}\)
- B \(\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{4-}\)
- C \(\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{4-}\)
- D \(\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}\)
Answer & Solution
Correct Answer
(D) \(\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}\)
Step-by-step Solution
Detailed explanation
The configuration \(\mathrm{t}_{2 \mathrm{~g}}^3 \mathrm{e}_{\mathrm{g}}^1\) represents a total of \(3+1=\) 4 electrons in the d-subshell with all electrons unpaired as there is a weak-field ligand. Thus, \(\mathrm{Mn}\) is in +3 state and the complex 'A' will be…
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