AP EAMCET · PHYSICS · Waves and Sound
The equation of a stationary wave is \(y=20 \sin (\pi x)\) \(\cos (\omega t)\), where \(x, y\) are in metre and \(t\) is in second. The distance between a node and its adjacent antinode is
- A \(25 \mathrm{~cm}\)
- B \(100 \mathrm{~cm}\)
- C \(50 \mathrm{~cm}\)
- D \(200 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(50 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Equation of wave, \[ \mathrm{y}=20 \sin (\pi x) \] General equation of wave, \[ \mathrm{y}=\mathrm{A} \sin (\mathrm{K} x) \] on compairing, \(\mathrm{K}=\pi\) \[ \frac{2 \pi}{\lambda}=\pi \Rightarrow \lambda=2 \mathrm{~m} \] Distance between node and anti node is given as:…
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