AP EAMCET · PHYSICS · Ray Optics
If a microscope is placed in air, the minimum separation of two objects seen as distinct is 6 pm . If the same is placed in a medium of refractive index 1.5 , then the minimum separation of the two objects to see as distinct is
- A \(4 \mu \mathrm{~m}\)
- B \(6 \mu \mathrm{~m}\)
- C \(3 \mu \mathrm{~m}\)
- D \(9 \mu \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(4 \mu \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
In air, \(\mathrm{d}=6 \mu \mathrm{~m}, \mathrm{n}=1.5\) In medium, \(\mathrm{d}^{\prime}=\frac{\mathrm{d}}{\mathrm{n}}=\frac{6}{1.5}=4 \mu \mathrm{~m}\)
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