AP EAMCET · Maths · Pair of Lines
The equations of the lines perpendicular to \(x^2-5 x y+4 y^2=0\) and passing through \((2,1)\) is
- A \(4 x^2+5 x y+y^2-13 x-1=0\)
- B \(4 x^2+5 x y+y^2-5 x-10 y-7=0\)
- C \(4 x^2+5 x y+y^2-4 x-4 y-15=0\)
- D \(4 x^2+5 x y+y^2-21 x-12 y+27=0\)
Answer & Solution
Correct Answer
(D) \(4 x^2+5 x y+y^2-21 x-12 y+27=0\)
Step-by-step Solution
Detailed explanation
Given, lines are \(x-4 y=0\) and \(x-y=0\) Lines perpendicular to them and passing through \((2,1)\) are \(4 x+y-9=0\) and \(x+y-3=0\) \(\therefore\) Equation of pair of straight lines is…
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