AP EAMCET · Chemistry · Chemical Kinetics
The following equation is obtained for a first order reaction at 300 K .
\(\log _{10} \frac{\mathrm{k}}{\mathrm{~A}}=0.00174\)
What is the activation energy (in \(\mathrm{J} \mathrm{mol}^{-1}\) ) of the reaction?
\(\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)
- A \(10.0\)
- B \(100.0\)
- C \(0.1\)
- D \(1.0\)
Answer & Solution
Correct Answer
(A) \(10.0\)
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Detailed explanation
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