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AP EAMCET · PHYSICS · Mechanical Properties of Fluids

Energy needed in breaking a liquid drop of radius \(R\), into \(n\) smaller drops each of radius \(r\), is [T- Surface tension of the liquid]

  1. A \(\left(4 \pi r^2 n-4 \pi R^2\right) T\)
  2. B \(\left(\frac{4}{3} \pi r^3 n-\frac{4}{3} \pi R^3\right) T\)
  3. C \(\left(4 \pi R^2-4 \pi r^2\right) n T\)
  4. D \(\left(4 \pi R^2-n 4 \pi r^2\right) / T\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(4 \pi r^2 n-4 \pi R^2\right) T\)

Step-by-step Solution

Detailed explanation

We have \(\Delta \mathrm{U}=\) (surface energy of bigger drop) - (surface energy of lower drop)…
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