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AP EAMCET · PHYSICS · Gravitation

Find the gravitational force between two stones, each of mass \(2 \mathrm{~kg}\) and separated by a distance \(1 \mathrm{~m}\) in vacuum.

  1. A 0
  2. B \(6.675 \times 10^{-5} \mathrm{~N}\)
  3. C \(6.675 \times 10^{-11} \mathrm{~N}\)
  4. D \(2.67 \times 10^{-10} \mathrm{~N}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2.67 \times 10^{-10} \mathrm{~N}\)

Step-by-step Solution

Detailed explanation

Given, masses of two stones, \(m=2 \mathrm{~kg}\) Separation, \(d=1 \mathrm{~m}\) Since, gravitational force, \(F=\frac{G m^2}{d^2}\) where, \(G=6.67 \times 10^{11} \mathrm{~N}-\mathrm{m}^2 \mathrm{~kg}^{-2}\)…
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