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AP EAMCET · PHYSICS · Center of Mass Momentum and Collision

A bullet of mass 10 g pierces through a plate A of mass 500 g and then gets embedded into a second plate B of mass 1.49 kg as shown in the figure. Initially the two plates A and B are at rest and move with same velocity after collision. The percentage loss in the initial kinetic energy of the bullet when it is between the plates A and B is_______. (Neglect any loss of material of the plates during the collision)

  1. A 25
  2. B 56.25
  3. C 43.75
  4. D 75
Verified Solution

Answer & Solution

Correct Answer

(C) 43.75

Step-by-step Solution

Detailed explanation

Let us suppose that the mass of the bullet is, m=10 g=10-2 kg and MA=12 kg,  MB=1.49 kg , now the loss of kinetic energy of a bullet is, ∆K.E.×100=-12mv12-12mu212mu2×100=-v12-u2u2×100∆K.E.×100=-v12u2-1×100…