AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A particle of mass \(4 m\) explodes into three pieces of masses \(m, m\) and \(2 \mathrm{~m}\). The equal masses move along \(X\)-axis and \(Y\)-axis with velocities \(4 \mathrm{~ms}^{-1}\) and \(6 \mathrm{~ms}^{-1}\) respectively. The magnitude of the velocity of the heavier mass is
- A \(\sqrt{17} \mathrm{~ms}^{-1}\)
- B \(2 \sqrt{13} \mathrm{~ms}^{-1}\)
- C \(\sqrt{13} \mathrm{~ms}^{-1}\)
- D \(\frac{\sqrt{13}}{2} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{17} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Let third mass particle \((2 \mathrm{~m}\) ) moves making angle \(\theta\) with \(X\)-axis. The horizontal component of velocity of \(2 \mathrm{~m}\) mass particle \(=u \cos \theta\) and vertical component \(=u \sin \theta\) From conservation of linear momentum in…
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