AP EAMCET · PHYSICS · Mechanical Properties of Fluids
Consider a circular ring of radius \(1,4 \mathrm{~cm}\) lying on the surface of a liquid. If a vertical force of \(0.022 \mathrm{~N}\) greater than the weight of the ring is required to lift this ring from the liquid surface, then the surface tension of the liquid is
- A \(0.085 \mathrm{Nm}^{-1}\)
- B \(0.125 \mathrm{Nm}^{-1}\)
- C \(0.250 \mathrm{Nm}^{-1}\)
- D \(0.465 \mathrm{Nm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(0.125 \mathrm{Nm}^{-1}\)
Step-by-step Solution
Detailed explanation
The given situation is shown below. Force required to lift the ring, \(F=2 \pi(r+r) \times T+W\) \(\Rightarrow \quad F=4 \pi r T+W\) Now given, \(F=0.022+W\) and \(\quad r=1.4 \mathrm{~cm}\) So, \(0.022+W=4 \pi \times 1.4 \times T+W\)…
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