AP EAMCET · Maths · Probability
If one ticket is selected at random from 30 tickets each with a distinct number from 1 to 30 , then the probability that the number on the selected ticket is a multiple of 3 or 5 is
- A \(\frac{14}{31}\)
- B \(\frac{7}{30}\)
- C \(\frac{14}{15}\)
- D \(\frac{7}{15}\)
Answer & Solution
Correct Answer
(D) \(\frac{7}{15}\)
Step-by-step Solution
Detailed explanation
No. of total events \(=30\) Multiples of 3 are \(3,6,9,12,15,18,21\), \(24,27,30\) Multiples of 5 are \(5,10,15,20,25,30\) Then multiples of 3 or 5 are : \(3,5,6,9,10,12,15\), \(18,20,21,24,25,27,30\) \(\therefore\) No. of favourable events \(=14\) The required probability…
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