AP EAMCET · PHYSICS · Atomic Physics
The ratio of minimum wave length of Balmer series to maximum wavelength in Brackett series in hydrogen spectrum is
- A 25:16
- B 4:36
- C 9:100
- D 100:9
Answer & Solution
Correct Answer
(C) 9:100
Step-by-step Solution
Detailed explanation
For hydrogen atom, \(\frac{1}{\lambda}=\mathrm{R}\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right)\) For Balmer series, \(\mathrm{n}_1=2, \mathrm{n}_2=3,4,5, \ldots . \infty\)…
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