AP EAMCET · PHYSICS · Oscillations
An object of mass \(2 \mathrm{~kg}\) is attached to a spring with spring constant \(8 \mathrm{Nm}^{-1}\). If the object is executing simple harmonic motion then the number of cycles it completes in \(66 \mathrm{~s}\) is
- A \(21\)
- B \(16\)
- C \(28\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(21\)
Step-by-step Solution
Detailed explanation
Time period of a spring mass system is \(T=2 \pi \sqrt{\frac{m}{k}}\) Here, \(\quad m=2 \mathrm{~kg}\) and \(k=8 \mathrm{~N} / \mathrm{m}\) So, time for 1 oscillation, \(T=2 \pi \sqrt{\frac{2}{8}}=2 \times \pi \times \frac{1}{2}\) or \(\quad T=\pi \mathrm{s}\) Number of cycles…
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