AP EAMCET · PHYSICS · Magnetic Effects of Current
Two long wires carrying current is \(8 \mathrm{~A}\) and \(6 \mathrm{~A}\) along \(\mathrm{x}\) axes and \(\mathrm{y}\) axes respectively. The magnetic field at the point \((2 \hat{i}+4 \hat{j})\) is
(Take \(\mu_{\mathrm{o}}=4 \pi \times 10^{-7}\) SI unit)
- A \(1 \times 10^{-6} \mathrm{~T}\)
- B \(2 \times 10^{-6} \mathrm{~T}\)
- C \(1 \times 10^{-7} \mathrm{~T}\)
- D \(2 \times 10^{-7} \mathrm{~T}\)
Answer & Solution
Correct Answer
(D) \(2 \times 10^{-7} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
We have \(\mathrm{B}_{\mathrm{P}}=\frac{\mu_0 \mathrm{i}_1}{2 \pi \mathrm{r}_1} \otimes+\frac{\mu_0 \mathrm{i}_2}{2 \pi \mathrm{r}_2} \odot\) \(\begin{aligned} & =2 \times 10^{-7}\left(\frac{6}{2}-\frac{8}{4}\right) \otimes \\ & =2 \times 10^{-7}(3-2) \otimes\end{aligned}\)…
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