AP EAMCET · PHYSICS · Gravitation
A satellite is launched into a circular orbit of radius \(R\) around earth while a second satellite is launched into a orbit of radius \(1.02 R\). The percentage difference in the time periods of the two satellites is :
- A 0.7
- B 1
- C 1.5
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
From Kepler's law, \(T^2 \propto R^3 \Rightarrow \frac{T_1^2}{T_2^2}=\frac{R_1^3}{R_2^3}\) \(\frac{T_1}{T_2}=\left(\frac{R_1}{R_2}\right)^{3 / 2}=\left(\frac{R}{1.02 R}\right)^{3 / 2}\) \(\Rightarrow \quad \frac{T_1}{T_2}=\left(\frac{50}{51}\right)^{3 / 2}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from PHYSICS
- An infinitely long straight conductor is bent into the shape as shown below. It carries a current of I ampere and the radius of the circular loop is R metre. Then, the magnitude of magnetic induction at the centre of the circular loop is
AP EAMCET 2009 Easy - It is possible to project a particle with a given velocity in two possible ways so as to make them pass through a point \(p\) at a horizontal distance \(r\) from the point of projection. If \(t_1\) and \(t_2\) are times taken to reach this point in two possible ways, then the product \(t_1 t_2\) is proportional toAP EAMCET 2012 Easy
- Two charges and are placed at points A and B separated by a distance of . Find the electric field at a point P on the perpendicular bisector of A B, at a distance of from its mid-point.
AP EAMCET 2021 Medium - A particle is projected from the ground with an initial speed of \(v\) at an angle of projection \(\theta\). The average velocity of the particle between its time of projection and time it reaches highest point of trajectory isAP EAMCET 2013 Medium
- Assertion(A) In an elastic collision of two billiard balls, the total KE is conserved during the short time of collision of the balls
(i.e., when they are in contact).Reason(R) Energy spent against friction does not follow the law of conservation of energy.
CodesAP EAMCET 2021 Medium - Potential difference between the points \(P\) and \(Q\) in the circuit shown is
AP EAMCET 2020 Easy
More PYQs from AP EAMCET
- If the half lives of the first order reaction at \(350 \mathrm{~K}\) and \(300 \mathrm{~K}\) are 2 and 20 seconds respectively, the activation energy of the reaction in \(\mathrm{kJ} \mathrm{mol}^{-1}\) isAP EAMCET 2020 Medium
- Consider the following
Statement-I : Cane sugar is a disaccharide of \(\alpha\)-D-glucose and \(\beta\)-D-fructose
Statement-II : Milk sugar is a diasaccharide of \(\alpha\)-D-glucose and \(\beta\)-D-galactose
The correct answer isAP EAMCET 2025 Easy - The absorption coefficient value of a perfect black body isAP EAMCET 2024 Easy
- An angle between the curves \(x^2=3 y\) and \(x^2+y^2=4\) isAP EAMCET 2017 Medium
- If the displacement of a particle executing simple harmonic motion is given by \(\mathrm{x}=0.5 \cos (125.6 \mathrm{t})\), then the time period of oscillation of the particle is nearly
(Here x is displacement in metre and t is time in second)AP EAMCET 2025 Easy - If the line joining the points \(A(\alpha)\) and \(B(\beta)\) on the ellipse \(\frac{x^2}{25}+\frac{y^2}{9}=1\) is a focal chord, then one possible value of \(\cot \frac{\alpha}{2} \cdot \cot \frac{\beta}{2}\) isAP EAMCET 2019 Medium