AP EAMCET · PHYSICS · Thermodynamics
In a Carnot engine, the absolute temperature of the source is \(25 \%\) more than the absolute temperature of the sink. The efficiency of the engine is
- A \(10 \%\)
- B \(50 \%\)
- C \(25 \%\)
- D \(20 \%\)
Answer & Solution
Correct Answer
(D) \(20 \%\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}_2=\mathrm{T}, \mathrm{~T}_1=1.25 \mathrm{~T}\) \(\therefore\) Efficiency of cannot engine is \(\eta=1-\frac{T_2}{T_1}=1-\frac{T}{1.25 T}=\frac{1}{5}\) \(\therefore \quad \% \eta=\frac{1}{5} \times 100=20 \%\)
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