AP EAMCET · Chemistry · Thermodynamics (C)

At $60 ° C$ , dinitrogen tetroxide is fifty percent dissociated. Find its standard free energy change at this temperature and one atmosphere. [ Given: $\log 1.33 = 0.1239$ ]

A $-650 J . mol^{- 1}$
B $- 830 J . {mol}^{- 1}$
C $- 790 J . {mol}^{- 1}$
D $- 875 J \cdot {mol}^{- 1}$

Verified Solution

Answer & Solution

Correct Answer

(C) $- 790 J . {mol}^{- 1}$

Step-by-step Solution

Detailed explanation

The reaction showing the dissociation will be: N2O4(s)⇌2NO2(g)t=01 mol0 molt=teq0.5 mol1 mol Clearly, from this equation we can say that the total number of moles is 0.5+1=1.5 mol Hence, the partial pressure for the molecule will be…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the following

List-I (Reaction)	List-II (Catalyst)
A) Hydrogenation of vegetable oils	I. Ni
B) Decomposition of potassium chlorate	II. $\mathrm{MnO}_2$
C) Oxidation of $\mathrm{SO}_2$ in lead chamber process	III. Pt
D) Oxidation of ammonia in Ostwald's process	IV. $\mathrm{NO}(\mathrm{g})$

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At 60°C, dinitrogen tetroxide is fifty percent dissociated. Find its standard free energy change at this temperature and one atmosphere. [ Given: log1.33=0.1239 ]

Step-by-step Solution

At $60 ° C$ , dinitrogen tetroxide is fifty percent dissociated. Find its standard free energy change at this temperature and one atmosphere. [ Given: $\log 1.33 = 0.1239$ ]