AP EAMCET · Maths · Properties of Triangles
In a triangle ABC, if \(\sin \frac{\mathrm{A}}{2}=\frac{1}{4} \sqrt{\frac{3}{5}}, \mathrm{a}=2, \mathrm{c}=5\) and b is an integer, then the area (in sq. units) of triangle ABC is
- A \(\frac{\sqrt{297}}{4}\)
- B \(\frac{\sqrt{231}}{4}\)
- C \(\frac{\sqrt{385}}{4}\)
- D \(\frac{\sqrt{185}}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{\sqrt{231}}{4}\)
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