AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
An explosion blows a stationary rock into three parts. Two parts of masses \(1 \mathrm{~kg}\) and \(2 \mathrm{~kg}\) moves at right angles to one another with velocities \(12 \mathrm{~ms}^{-1}\) and \(8 \mathrm{~ms}^{-1}\), respectively. If the velocity of third part is 4 \(\mathrm{ms}^{-1}\), the mass of the rock is
- A \(8 \mathrm{~kg}\)
- B \(5 \mathrm{~kg}\)
- C \(17 \mathrm{~kg}\)
- D \(3 \mathrm{~kg}\)
Answer & Solution
Correct Answer
(A) \(8 \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
Given, \(m_1=1 \mathrm{~kg}, m_2=2 \mathrm{~kg}\), \(v_1=12 \mathrm{~ms}^{-1}, v_2=8 \mathrm{~ms}^{-1} \text { and } v_3=4 \mathrm{~ms}^{-1}\) Since, in the explosion of stationary rock, the momentum is conserved, so…
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