AP EAMCET · Chemistry · Solid State
Ag crystallises in fcc lattice. What is the total number of tetrahedral voids present in \(540 \mathrm{~g}\) of Ag metal? \(\left(N_A=\right.\) Avagadro number; \(\mathrm{Ag}\) atomic weight \(=108 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A \(10 N_A\)
- B \(20 N_A\)
- C \(40 N_A\)
- D \(60 N_A\)
Answer & Solution
Correct Answer
(A) \(10 N_A\)
Step-by-step Solution
Detailed explanation
Ag crystallises in fcc lattice. Each unit cell contains 4 atoms and 8 tetrahedral voids. The mass of one \(\mathrm{Ag}\)-atom \[ =\frac{\text { Atomic mass }}{N_A}=\frac{108 \mathrm{~g} \mathrm{~mol}^{-1}}{N_A} \] The mass of one unit cell will be…
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