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AP EAMCET · Maths · Permutation Combination

The number of all four digit numbers which begin with 4 and end with either zero or five is

  1. A \(200\)
  2. B \(64\)
  3. C \(256\)
  4. D \(32\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(200\)

Step-by-step Solution

Detailed explanation

The required no. of all four digit number \(=1 \times 10^2 \times 2=200\)