AP EAMCET · PHYSICS · Dual Nature of Matter
An electron of charge \(e\) and mass \(m\) moving with an initial velocity \(v_0 \hat{\mathbf{i}}\) is subjected to all electric field \(E_0 \hat{\mathbf{j}}\). The de-Broglie wavelength of the electron at a time \(t\) is (Initial de-Broglie wavelength of the electron \(\left.=\lambda_0\right)\)
- A \(\lambda_0\)
- B \(\lambda_0 \sqrt{1+\frac{e^2 E_0^2 t^2}{m^2 v_0^2}}\)
- C \(\frac{\lambda_0}{\sqrt{1+\frac{e^2 E_0^2 t^2}{m^2 v_0^2}}}\)
- D \(\frac{\lambda_0}{\left(1+\frac{e^2 E_0^2 t^2}{m v_0^2}\right)}\)
Answer & Solution
Correct Answer
(C) \(\frac{\lambda_0}{\sqrt{1+\frac{e^2 E_0^2 t^2}{m^2 v_0^2}}}\)
Step-by-step Solution
Detailed explanation
\(\because\) de-Broglie relation of a charged particles, \[ \lambda=\frac{h}{m v} \] Velocity of charged particle at time \(t\), \[ \mathbf{v}=v_0 \hat{\mathbf{i}}+\frac{e E_0}{m} t \hat{\mathbf{j}} \text { or }|v|=\sqrt{v_0^2+\left(\frac{e E_0}{m} t\right)^2} \] Hence,…
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