AP EAMCET · PHYSICS · Magnetic Effects of Current
A wire shaped in a regular hexagon of side 2 cm carries a current of 4A. The magnetic field at the centre of hexagon is

- A \(4 \sqrt{3} \times 10^{-5} \mathrm{~T}\)
- B \(8 \sqrt{3} \times 10^{-5} \mathrm{~T}\)
- C \(\sqrt{3} \times 10^{-5} \mathrm{~T}\)
- D \(6 \sqrt{3} \times 10^{-5} \mathrm{~T}\)
Answer & Solution
Correct Answer
(B) \(8 \sqrt{3} \times 10^{-5} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{r}=\frac{\frac{\mathrm{a}}{2}}{\tan 30^{\circ}}=\frac{\sqrt{3} \mathrm{a}}{2}=\sqrt{3} \mathrm{~cm}\) \(\therefore\) Magnetic field at centre 0 ,…
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