AP EAMCET · Chemistry · States of Matter
If two gases \(\mathrm{CH}_4\) and \(\mathrm{SO}_2\), are allowed to enter from the two ends of a \(1 \mathrm{~km}\) long vacuum tube at the same time, where will the gases meet from the \(\mathrm{CH}_4\) end?
- A \(500 \mathrm{~m}\)
- B \(620 \mathrm{~m}\)
- C \(667 \mathrm{~m}\)
- D \(720 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(667 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{M}_{\mathrm{CH}_4}=16 ;\left(\mathrm{C}_{\mathrm{CH}_4}\right)_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{RT}}{16}}=\frac{\sqrt{3 \mathrm{RT}}}{4} \mathrm{~m} / \mathrm{s}\)…
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