AP EAMCET · PHYSICS · Oscillations
A pendulum is oscillating at a frequency of \(8 \mathrm{~Hz}\). Suddenly the string of the pendulum is clamped at its midpoint then the new frequency of oscillations is
- A \(16 \mathrm{~Hz}\)
- B \(13.8 \mathrm{~Hz}\)
- C \(11.28 \mathrm{~Hz}\)
- D \(5.7 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(C) \(11.28 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{f}=\frac{1}{2 \pi} \sqrt{\frac{\mathrm{g}}{\ell}}\)…
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