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AP EAMCET · PHYSICS · Magnetic Properties of Matter

A vibration magnetometer is used at two different places \(\mathrm{A}\) and \(\mathrm{B}\) on the earth. The time period of a magnet suspended freely in the magnetometer at \(\mathrm{A}\) is twice that at \(\mathrm{B}\). If the horizontal component of the earth's magnetic field at \(\mathrm{B}\) is \(32 \times 10^{-6} \mathrm{~T}\), then its value at \(\mathrm{A}\) is

  1. A \(\mathrm{H}_{\mathrm{A}}=8 \times 10^{-6} \mathrm{~T}\)
  2. B \(\mathrm{H}_{\mathrm{A}}=32 \times 10^{-6} \mathrm{~T}\)
  3. C \(\mathrm{H}_{\mathrm{A}}^{\mathrm{A}}=4 \times 10^{-6} \mathrm{~T}\)
  4. D \(\mathrm{H}_{\mathrm{A}}=16 \times 10^{-6} \mathrm{~T}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{H}_{\mathrm{A}}=8 \times 10^{-6} \mathrm{~T}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{I}}{\mathrm{MB}_{\mathrm{H}}}} \\ & \mathrm{T} \propto \frac{1}{\sqrt{\mathrm{B}_{\mathrm{H}}}}\end{aligned}\)…
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