AP EAMCET · PHYSICS · Semiconductors
In a common emitter transistor amplifier the resistance of collector is \(3 \mathrm{k} \Omega\). If the current amplification factor is 100 and the base resistance is \(2 \mathrm{k} \Omega\), then the power gain of the transistor is
- A \(150\)
- B \(10000\)
- C \(1500\)
- D \(15000\)
Answer & Solution
Correct Answer
(D) \(15000\)
Step-by-step Solution
Detailed explanation
\(A_P = \beta^2 \frac{R_C}{R_B}\) \(A_P = (100)^2 \times \frac{3 \, \mathrm{k} \Omega}{2 \, \mathrm{k} \Omega}\) \(A_P = 10000 \times 1.5 = 15000\)
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