AP EAMCET · PHYSICS · Work Power Energy
A block of mass \(m=25 \mathrm{~kg}\) sliding on a smooth horizontal surface with a velocity \(v=3 \mathrm{~ms}^{-1}\) meets the spring of spring constant \(k=100 \mathrm{~N} / \mathrm{m}\) fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as it returns to the original position respectively are
- A \(1.5 \mathrm{~m},-3 \mathrm{~ms}^{-1}\)
- B \(1.5 \mathrm{~m}, 0.01 \mathrm{~ms}^{-1}\)
- C \(1.0 \mathrm{~m}, 3 \mathrm{~ms}^{-1}\)
- D \(0.5 \mathrm{~m}, 2 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.5 \mathrm{~m},-3 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie, \(\frac{1}{2} m v^2=\frac{1}{2} k x^2\) where \(x\) is compression in spring. \(x=\sqrt{\frac{m v^2}{k}}\)…
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