AP EAMCET · PHYSICS · Motion In One Dimension
A train travels from city- \(A\) to city- \(B\) with a constant speed of \(18 \mathrm{~ms}^{-1}\) and returns back to city- \(A\) with a constant speed of \(36 \mathrm{~ms}^{-1}\). Find its average speed during the journey.
- A \(\frac{72}{5} \mathrm{~ms}^{-1}\)
- B \(\frac{36}{3} \mathrm{~ms}^{-}\)
- C \(\frac{72}{3} \mathrm{~ms}^{-1}\)
- D \(\frac{36}{5} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(\frac{72}{3} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Given that, speed of train from city- \(A\) to city- \(B\), \[ v_1=18 \mathrm{~m} / \mathrm{s} \] Speed of train from city- \(B\) to city- \(A\) \[ v_2=36 \mathrm{~m} / \mathrm{s} \] In this process, the distance travelled by train from \(A\) to \(B\) and \(B\) to \(A\) will be…
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