AP EAMCET · Chemistry · Thermodynamics (C)
Molar enthalpy change for vapourisation of \(1.0 \mathrm{~mol}\) of water at \(1.0 \mathrm{bar}\) and \(100^{\circ} \mathrm{C}\) is \(41.0 \mathrm{~kJ} \mathrm{~mol}^{-1}\). If water vapour is assumed to be an ideal gas, the internal energy change for \(1.0 \mathrm{~g}\) of water in \(\mathrm{kJ}\) is
- A \(1.053\)
- B \(4.212\)
- C \(3.159\)
- D \(2.106\)
Answer & Solution
Correct Answer
(D) \(2.106\)
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