AP EAMCET · PHYSICS · Magnetic Effects of Current
A tightly wound coil of 200 turns and of radius 20 cm carrying current 5 A . Magnetic field at the centre of the coil is
- A \(3.14 \times 10^{-3} \mathrm{~T}\)
- B \(3.14 \times 10^{-2} \mathrm{~T}\)
- C \(6.28 \times 10^{-4} \mathrm{~T}\)
- D \(6.28 \times 10^{-3} \mathrm{~T}\)
Answer & Solution
Correct Answer
(A) \(3.14 \times 10^{-3} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
For tightly wound coil, \(\mathrm{N}=200, \mathrm{r}=20 \mathrm{~cm}, \mathrm{I}=5 \mathrm{~A}\) \(\therefore\) Magnetic field at the centre of coil,…
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