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AP EAMCET · Maths · Vector Algebra

Let \(\mathbf{F}=2 \hat{i}+2 \hat{j}+5 \hat{k}, A=(1,2,5)\), \(B=(-1,-2,-3)\) and \(\mathbf{B A} \times \mathbf{F}=4 \hat{i}+6 \hat{j}+2 \lambda \hat{k}\), then \(\lambda=\)

  1. A \(0\)
  2. B \(1\)
  3. C \(2\)
  4. D \(-2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-2\)

Step-by-step Solution

Detailed explanation

Given, \(\begin{aligned} & \mathbf{F}=2 i+2 j+5 k, A=(1,2,5) \\ & B=(-1,-2,-3) \\ & \mathbf{B A}=\mathbf{A}-\mathbf{B}=(\hat{i}+2 \hat{j}+5 \hat{k})-(-\hat{i}-2 \hat{j}-3 \hat{k}) \\ & \mathbf{B A}=2 \hat{i}+4 \hat{j}+8 \hat{k}\end{aligned}\)…