AP EAMCET · PHYSICS · Current Electricity
The potential difference across a conducting wire of length 20 cm is 30 V. If the electron mobility is \(2 \times 10^{-6} \mathrm{~m}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}\), then the drift velocity of the electrons is
- A \(3 \times 10^{-3} \mathrm{~ms}^{-1}\)
- B \(1.5 \times 10^{-3} \mathrm{~ms}^{-1}\)
- C \(1.5 \times 10^{-4} \mathrm{~ms}^{-1}\)
- D \(3 \times 10^{-4} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(D) \(3 \times 10^{-4} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\(E = V/L = 30 \text{ V} / 0.20 \text{ m} = 150 \text{ V/m}\) \(v_d = \mu E = (2 \times 10^{-6} \mathrm{~m}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}) \times (150 \mathrm{~V/m}) = 3 \times 10^{-4} \mathrm{~ms}^{-1}\)
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