AP EAMCET · PHYSICS · Mechanical Properties of Fluids
If \(\mathrm{S}_1, \mathrm{~S}_2\) and \(\mathrm{S}_3\) are the tensions at liquid-air, solid-air and solid-liquid interfaces respectively, and \(\theta\) is the angle of contact at the solid-liquid interface, then
- A \(\mathrm{S}_1, \cos \theta+\mathrm{S}_2 \sin \theta=\mathrm{S}_3\)
- B \(S_1 \cos \theta+S_3=S_2\)
- C \(S_2 \cos \theta+S_3=S_1\)
- D \(S_3 \cos \theta+S_1=S_2\)
Answer & Solution
Correct Answer
(B) \(S_1 \cos \theta+S_3=S_2\)
Step-by-step Solution
Detailed explanation
At equilibrium of liquid drop, \(S_2=S_1 \cos \theta+S_3\)
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