AP EAMCET · PHYSICS · Electromagnetic Induction
A thin wire of length ' \(L\) ' made of an insulating material is bent to form a circular loop and a positive charge ' \(\mathrm{q}\) ' is given so that it is distributed uniformly around the circumference of the loop. The loop is then rotated with an angular speed ' \(\omega\) ' about an axis passing through its centre. If a uniform magnetic field B directed parallel to the plane of the loop is applied then the magnitude of the magnetic torque on the loop is
- A \(\frac{\mathrm{q} \omega \mathrm{L}^2 \mathrm{~B}}{8 \pi^2}\)
- B \(\frac{\mathrm{q} \omega \mathrm{L}^2 \mathrm{~B}}{4 \pi^2}\)
- C \(\frac{\mathrm{q} \omega \mathrm{L}^2 \mathrm{~B}}{2 \pi^2}\)
- D \(\frac{\mathrm{q} \omega \mathrm{L}^2 \mathrm{~B}}{\pi^2}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{q} \omega \mathrm{L}^2 \mathrm{~B}}{8 \pi^2}\)
Step-by-step Solution
Detailed explanation
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