AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
The centre of mass of a homogenous semi-circular plate of radius \(\mathrm{r}\) is located at \(\mathrm{A}\) as shown in the figure. The distance OA is

- A \(\frac{2r}{3 \pi}\)
- B \(\frac{4 r}{3 \pi}\)
- C \(\frac{3r}{2 \pi}\)
- D \(\frac{r}{\pi}\)
Answer & Solution
Correct Answer
(B) \(\frac{4 r}{3 \pi}\)
Step-by-step Solution
Detailed explanation
The COM of a homogeneous semi-circular plate is located at \(\frac{4 \mathrm{r}}{3 \pi}\) distance from ' \(\mathrm{O}\) '. So, \(O A=\frac{4 r}{3 \pi}\)
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