AP EAMCET · PHYSICS · Ray Optics
A person can see objects clearly when they lie between 40 cm and 400 cm from his eye. In order to increase the maximum distance of distant vision to infinity, the type of lens and power of correction lens required respectively are
- A Convex, 0.25 Dioptre
- B Concave, -0.25 Dioptre
- C Concave, -0.5 Dioptre
- D Convex, 0.5 Dioptre
Answer & Solution
Correct Answer
(B) Concave, -0.25 Dioptre
Step-by-step Solution
Detailed explanation
\(\mathrm{u}=-\infty, \mathrm{v}=-400 \mathrm{~cm}\) By lens formula, \(\begin{aligned} & \frac{1}{f}=\frac{1}{v}-\frac{1}{u}=\frac{1}{-400}-\frac{1}{-\infty} \\ & \therefore \quad f=-400 \mathrm{~cm} \end{aligned}\) \(\therefore \quad\) Power of lens is given by…
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