AP EAMCET · Maths · Circle
The equation of a circle passing through the point \((2,8)\), touching the lines \(4 x-3 y-24=0\) and \(4 x+3 y-42=0\) and having the \(x\) coordinate of its centre less than or equal to 8 is
- A \(x^2+y^2+2 x-8 y-8=0\)
- B \(x^2+y^2-4 x-6 y-12=0\)
- C \(x^2+y^2+4 x-10 y+4=0\)
- D \(x^2+y^2-6 x-4 y-24=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-4 x-6 y-12=0\)
Step-by-step Solution
Detailed explanation
By the property of distance,…
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