AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
Two wooden blocks of mass \(M_1\) and \(M_2\) rest on a frictionless table. \(A\) bullet of mass \(m\) is fired at \(M_1\) with speed \(v\) which embedded in it and the two together finally collide with \(M_2\). Find the velocity of \(M_2\) after collision. (Ignore any energy loss and treat the problem to be one dimensional)
- A \(\frac{2 m v}{M_1+M_2+m}\)
- B \(\frac{m v}{M_1+M_2+m}\)
- C \(\frac{\left(M_1+M_2+m\right) v}{M_1+M_2+m}\)
- D \(\frac{M_1+M_2}{M_1+M_2+m} v\)
Answer & Solution
Correct Answer
(A) \(\frac{2 m v}{M_1+M_2+m}\)
Step-by-step Solution
Detailed explanation
( ) For an elastic collision of 2 masses \(m_1\) and \(m_2\) with initial velocities \(u_1\) and \(u_2\), final velocities of masses after collision are \( v_1=\left(\frac{m_1-m_2}{m_1+m_2}\right) u_1+\frac{2 m_2 u_2}{\left(m_1+m_2\right)} \) and…
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