AP EAMCET · PHYSICS · Current Electricity
A straight wire of resistance \(R\) is bent in the shape of a square. A cell of emf 12 V is connected between two adjacent corners of the square. The potential difference across any diagonal of the square is
- A 8 V
- B 18 V
- C 6 V
- D 12 V
Answer & Solution
Correct Answer
(A) 8 V
Step-by-step Solution
Detailed explanation
\begin{aligned} & R_{A D}=\frac{\frac{3 R}{4} \times \frac{R}{4}}{R}=\frac{3 R}{16} \Omega \\ \therefore & I=\frac{V}{R_{A D}}=\frac{12}{\frac{3 R}{16}}=\frac{64}{R} \\ \therefore & I_1=\left(\frac{\frac{R}{4}}{R}\right) I \\ = & \frac{1}{4} \times \frac{64}{R}=\frac{16}{R} \\…
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