AP EAMCET · Maths · Permutation Combination
In how many ways a committee of a 6 members can be formed out of 10 members but always consisting of a specified member ?
- A \(\frac{1}{2}{ }^9 P_5\)
- B \({ }^9 P_5\)
- C \({ }^9 \mathrm{C}_5\)
- D \(\frac{1}{2}{ }^9 C_5\)
Answer & Solution
Correct Answer
(C) \({ }^9 \mathrm{C}_5\)
Step-by-step Solution
Detailed explanation
As the committee consists a specified member out of 6 members, then we need to select only 5 members out of 9 remaining members and it can be done is \({ }^9 C_5\) ways. Hence, option (c) is correct.
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