AP EAMCET · PHYSICS · Rotational Motion
A thin uniform circular disc rolls with a constant velocity without slipping on a horizontal surface. Its total kinetic energy is
- A \(\text { three times its rotational kinetic energy }\)
- B \(\text { three times its translational kinetic energy }\)
- C \(\text { one and half times its rotational kinetic energy }\)
- D \(\text { twice its translational kinetic energy }\)
Answer & Solution
Correct Answer
(A) \(\text { three times its rotational kinetic energy }\)
Step-by-step Solution
Detailed explanation
\( I = \frac{1}{2}mr^2 \) \( K_{rotational} = \frac{1}{2}I\omega^2 = \frac{1}{2}(\frac{1}{2}mr^2)(v/r)^2 = \frac{1}{4}mv^2 \) \( K_{translational} = \frac{1}{2}mv^2 \) \( K_{total} = K_{translational} + K_{rotational} = \frac{1}{2}mv^2 + \frac{1}{4}mv^2 = \frac{3}{4}mv^2 \)…
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