AP EAMCET · PHYSICS · Motion In One Dimension
The time of flight of a vertically projected stone is \(8 \mathrm{~s}\). The position of the stone after \(6 \mathrm{~s}\) from the ground is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(20 \mathrm{~m}\)
- B \(60 \mathrm{~m}\)
- C \(75 \mathrm{~m}\)
- D \(40 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(60 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Time of flight \(\mathrm{t}=\frac{2 \mathrm{u} \sin \theta}{\mathrm{g}}\) or, \(8=\frac{2 \times \mathrm{u} \times 1}{10}\) \(\Rightarrow \mathrm{u}=40 \mathrm{~m} / \mathrm{s}\) \(\therefore\) The position of the stone after \(6 \mathrm{~s}\) from the ground.…
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