AP EAMCET · PHYSICS · Wave Optics
The angle between the axes of a polariser and an analyser is \(45^{\circ}\). If the intensity of the unpolarized light incident on the polariser is 1 , then the intensity of the light emerged from the analyser is
- A 2 I
- B \(\frac{\mathrm{I}}{2}\)
- C I
- D \(\frac{I}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{I}{4}\)
Step-by-step Solution
Detailed explanation
The intensity of light after passing through polariser is \(\mathrm{I}_1=\frac{\mathrm{I}}{2}\) The intensity of light after passing through analyses is \(I_2=I_1 \cos ^2 \theta=\frac{I}{2} \cos ^2 45^{\circ}=\frac{I}{2} \times\left(\frac{1}{\sqrt{2}}\right)^2=\frac{I}{4}\)
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