AP EAMCET · Maths · Hyperbola
The equation of one of the tangents drawn from the poin \((0,1)\) to the hyperbola \(45 x^2-4 y^2=5\) is
- A \(4 y+5=0\)
- B \(3 x+4 y-4=0\)
- C \(5 x-6 y+6=0\)
- D \(9 x-2 y+2=0\)
Answer & Solution
Correct Answer
(D) \(9 x-2 y+2=0\)
Step-by-step Solution
Detailed explanation
Let equation of tangent passing \((0,1)\) and slope \(m\) be \(y-1=m(x-0) \Rightarrow y=m x+1\) Intersection with hyperbola \(45 x^2-4 y^2=5\) \(\begin{aligned} & 45 x^2-4(m x+1)^2=5 \\ & \Rightarrow\left(45-4 m^2\right) x^2-8 m x-9=0 \end{aligned}\) For \(y=m x+1\) to be…
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