AP EAMCET · PHYSICS · Electromagnetic Induction
A solenoid has 2000 turns wound over a length of \(0.30 \mathrm{~m}\). The area of its cross-section is \(1.2 \times 10^{-3} \mathrm{~m}\). Around its central section, a coil of 300 turns is wound. If an initial current of \(2 \mathrm{~A}\) in the solenoid is reversed in \(0.25 \mathrm{~s}\), the emf induced in the coil is equal to
- A \(6 \times 10^{-4} \mathrm{~V}\)
- B \(4.8 \times 10^{-2} \mathrm{~V}\)
- C \(6 \times 10^{-2} \mathrm{~V}\)
- D \(48 \times 10^3 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(4.8 \times 10^{-2} \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} N_1 & =2000 \\ L & =0.30 \mathrm{~m} \\ N_2 & =300 \end{aligned} \] \(\frac{d i}{d t}=\frac{2-(-2)}{0.25}=\frac{4}{0.25} \mathrm{As}^{-1}\)…
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