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AP EAMCET · Maths · Properties of Triangles

What is the value of (a-b)2cos2c2+(a+b)2sin2c2=

  1. A c2
  2. B a2+b2
  3. C a2+b2+c2
  4. D a2-b2+c2
Verified Solution

Answer & Solution

Correct Answer

(A) c2

Step-by-step Solution

Detailed explanation

Given that: (a-b)2cos2c2+(a+b)2sin2c2 =(a2-2ab+b2)cos2c2+(a2+2ab+b2)sin2c2 =(a2+b2)(cos2c2+sin2c2)+2ab(sin2c2-cos2c2) As we know that cos2A=cos2A-sin2A =(a2+b2)-2abcosC As we know that cosC=a2+b2-c22ab =(a2+b2)-2ab(a2+b2-c22ab) =c2
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