AP EAMCET · PHYSICS · Mechanical Properties of Solids
The elastic potential energy stored in a copper rod of length one metre and area of cross-section \(1 \mathrm{~mm}^2\) when stretched by 1 mm is
(Young's modulus of copper \(=1.2 \times 10^{11} \mathrm{Nm}^{-2}\) )
- A \(6 \times 10^{-2} \mathrm{~J}\)
- B \(3 \times 10^{-2} \mathrm{~J}\)
- C 60 J
- D 3 J
Answer & Solution
Correct Answer
(A) \(6 \times 10^{-2} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(U = \frac{1}{2} Y A \frac{(\Delta L)^2}{L}\) \(U = \frac{1}{2} (1.2 \times 10^{11}) (1 \times 10^{-6}) \frac{(1 \times 10^{-3})^2}{1}\) \(U = 0.6 \times 10^{11} \times 10^{-6} \times 10^{-6}\) \(U = 0.6 \times 10^{-1}\) \(U = 6 \times 10^{-2} \mathrm{~J}\)
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